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A solid cylinder of mass 20 kg rotates about its axis with angular speed 100 rad/s. The radius of the cylinder is 0.25 m. What is the kinetic energy associated with the rotation of the cylinder ? What is the magnitude of angular momentum of the cylinder about its axis ? |
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Answer» Solution :Given: M=20kg, `omega=100"rad"s^(-1), R=0.25m` M.I of the CYLINDER about its own AXIS, `I=1/2MR^(2)=1/2xx20xx(.25)^(2)` `=10xx0.0625=.625kgm^(2)` ROTATIONAL K.E. `I=1/2 I omega^(2)` `=1/2 xx0.625xx(100)^(2)` `=0.3125xx10^(4)=3125J` Angular momentum, `L=I omega=0.625xx100` `=62.5 kg m^(2)s^(-1)` |
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