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A solid cylinder of mass 3 kg and radius 10 cm is rotating about its axis with a frequency 20//pi. The rotational kinetic energy of the cylinder |
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Answer» `10 pi J` ANGULAR frequency `omega=2piv=(2pixx20)/(pi)=40 "rad"//s^(-1)` Moment offerta of the cylinder about its axis `=I=(1)/(2) mR^(2)xx3xx(0.1)^(2)=0.015 KG m^(2)` `K.F=(1)/(2) I omega^(2)=(1)/(2)xx0.015xx(40)^(2)=12 J` |
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