A solid cylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms^(-1). It collides with a horizontal spring of force constant 200 N m^(-1). The maximum compression produced in the spring will be

A solid cylinder of mass 3 kg is rolling on a horizontal surface with

1.	A solid cylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms^(-1). It collides with a horizontal spring of force constant 200 N m^(-1). The maximum compression produced in the spring will be
Answer» 0.5 m 0.6 m 0.7 m 0.2 m SOLUTION :At MAXIMUM compression the solid cylinder will stop. According to law of conservation of mechanical energy Loss in kinetic energy = Gain in potential energy of spring of cylinder `1/2 mv^2 + 1/2 I omega^2 = 1/2 k x^2` `1/2 mv^2+ 1/2 kx^2 " or " x^2 = 3/2 (mv^2)/(k)` Here, `m = 3 kg , V = 4 ms^(-1), k = 200 N m^(-1)` Substituting the given values , we get `x^2= (3 xx 3 xx 4 xx 4)/(2 xx 200)" or " x = 0.6 m`.