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A solid cylinder of mass `M` and radius `R` rolls without slipping down an inclined plane of length `L` and height `h`. What is the speed of its center of mass when the cylinder reaches its bottomA. `sqrt((3)/(4))gh`B. `sqrt((4)/(3)gh)`C. `sqrt(4gh)`D. `sqrt(2gh)` |
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Answer» Correct Answer - B `Mgh = (1)/(2) I omega^(2)+(1)/(2)mv^(2)` `Mgh = (1)/(2)xx(3)/(2)mv^(2)rArr v=sqrt((4)/(3)gh)` |
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