1.

A solid has a bcc structure. If the distance of closest approach between the two atoms is `1.73.^(@)A`. The edge length of the cell isA. 200 pmB. `(sqrt3)/(sqrt2) pm `C. 142.2 gmD. `sqrt2`

Answer» Correct Answer - A
`r_("atom") = (sqrt3)/(4)` a , Also closest approach in bcc lattice is `1/2` of body diagonal , i.e. `(sqrt3)/(2) a = 1.73 Å`
or `a=(1.73xx2)/(sqrt3) = 1.966Å = 199.6` pm


Discussion

No Comment Found

Related InterviewSolutions