A solid made up of ions of `A` and `B` possess edge length of unit cell of `0.5664nm` has four formula units. Among the two ions, the smaller one occupy the interstitial void and the larger ions occupy the space lattice with ccp type of arrangement. One molecule of solid has mass `9.712xx10^(-23)g.` The solide `AB` is supposed to show `:`A. Schottky defectB. Frenkel defectC. non`-` stoichiometric defectD. none of these

A solid made up of ions of `A` and `B` possess edge length of unit cel

1.	A solid made up of ions of `A` and `B` possess edge length of unit cell of `0.5664nm` has four formula units. Among the two ions, the smaller one occupy the interstitial void and the larger ions occupy the space lattice with ccp type of arrangement. One molecule of solid has mass `9.712xx10^(-23)g.` The solide `AB` is supposed to show `:`A. Schottky defectB. Frenkel defectC. non`-` stoichiometric defectD. none of these
Answer» Correct Answer - A `AB` shows Schottky defect due to missing of one `A^(+)` and one `B^(-)` ion like `NaCl`.

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