A solid made up of ions of `A` and `B` possess edge length of unit cell of `0.5664nm` has four formula units. Among the two ions, the smaller one occupy the interstitial void and the larger ions occupy the space lattice with ccp type of arrangement. One molecule of solid has mass `9.712xx10^(-23)g.` The structural arrangement of `AB` is `:`A. cubicB. octahedralC. tetrahedralD. triangular

A solid made up of ions of `A` and `B` possess edge length of unit cel

1.	A solid made up of ions of `A` and `B` possess edge length of unit cell of `0.5664nm` has four formula units. Among the two ions, the smaller one occupy the interstitial void and the larger ions occupy the space lattice with ccp type of arrangement. One molecule of solid has mass `9.712xx10^(-23)g.` The structural arrangement of `AB` is `:`A. cubicB. octahedralC. tetrahedralD. triangular
Answer» Correct Answer - b `(r_(A^(+)))/(r_(B^(-)))=(0.826)/(1.994)=0.414,` `i.e.,` octahedral arrangement

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