InterviewSolution
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A solid metallic cuboid of dimensions 18 cm × 36 cm × 72 cm is melted and recast into 8 cubes of the same volume. What is the ratio of the total surface area of the cuboid to the sum of the lateral surface areas of all 8 cubes? 1. 2 : 32. 7 : 123. 4 : 74. 7 : 8 |
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Answer» Correct Answer - Option 4 : 7 : 8 Given: A solid metallic cuboid of dimensions 18 cm × 36 cm × 72 cm where l = 18 cm, b = 36 cm and h = 72 cm It is melted and recast into 8 cubes of the same volume. Concept used: The volume of cuboid = lbh The total surface area of the cuboid = 2(lb + bh + hl) Where l = length, b = breadth and h = height The volume of cube = a3 The lateral surface area of cube = 4 × a2 Where a = side of cube Explanation: according to the question, lbh = 8 × a3 ⇒ 18 × 36 × 72 = 8 × a3 ⇒ a3 = 18 × 36 × 9 ⇒ a = √(9 × 2 × 9 × 2 × 2 × 9) ⇒ a = 18 cm now, according to the question, 2(lb + bh + hl) : 8 × 4 × a2 ⇒ 2(18 × 36 + 36 × 72 + 72 × 18) : 8 × 4 × (18)2 ⇒ 2 × 18 × 36(1 + 4 + 2) : 8 × 4 × 18 × 18 ⇒ 36 × 36 × 7 : 32 × 18 × 18 ⇒ 7 : 8 ∴ The ratio is 7 : 8. |
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