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A solid sphere has a radius of 1.5 cm and a mass of 0.038 kg. Calculate the specific gravity or relative density of the sphere. |
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Answer» Solution :Radius of the sphere R = 1.5 cm, MASS m = 0.038 kg Volume of sphere `V = 4/3 pi R^2 = 4/3 XX (3.14) xx (1.5 xx 10^(-2))^(3) = 1.413 xx 10^(-5) m^(3)` Therefore, DENSITY `rho = m/V = (0.038 kg)/(1.413 xx 10^(-5) m^3) = 2690 kg m^(-3)` Hence, the SPECIFIC of the sphere `= (2690)/(1000) = 2.69` |
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