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A solid sphere is in rolling motion . In rolling motion a body possesses translational kinetic energy (K_(t)) aswell as rotational kinetic energy (K_(r)) simultaneously . The ratio K_(t) : (K_(t) + K_(r)) for the sphere is |
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Answer» `7 : 10` Rotational kinetic energy `K_(R) = (1)/(2) I omega^(2)` `therefore K_(t) + K_(r) = (1)/(2) m v^(2) + (1)/(2) I omega^(2) = (1)/(2) mv^(2) + (1)/(2) ((2)/(5) mr^(2)) ((v)/(r))^(2)` `therefore K_(t) + K_(r) = (7)/(10) mv^(2) [ because I = (2)/(5) mr^(2)` (for SPHERE)] So , `(K_(t))/(K_(t) + K_(r)) = (5)/(7)` |
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