1.

A solid sphere is rolling down in the inclined plane, from rest without slipping. The angle of inclination with horizontal is 30^(@). The linear acceleration of the sphere is___(Assume g=10ms^(-2))

Answer»

(a) `28 ms^(-2)`
(b) `3.9ms^(-2)`
(c) `(25)/(7) ms^(-2)`
(d) `(1)/(20)ms^(-2)`

Solution :We know that `a=(g sin theta)/(1+(k^(2))/(R^(2)))=(g sin 30^(@))/(1+(2)/(5))`
`:.(k^(2))/(R^(2))` for solid SPHERE `=(2)/(5)`
`a=(10xx(1)/(2))/((7)/(5))=(25)/(7)=3.6 ms^(-2)`


Discussion

No Comment Found