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A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity `v m//s`. If it is to climb the inclined surface then `v` should be : A. `sqrt(10/7gh)`B. `gesqrt(2gh)`C. `2gh`D. `10/7gh` |
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Answer» Correct Answer - A `1/2MV^(2)+1/2Iomega^(2)geM"gh"` `Vgesqrt(10/7"gh")` |
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