A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity `v m//s`. If it is to climb the inclined surface then `v` should be : A. `ge sqrt((10)/(7)gh)`B. `ge sqrt(2gh)`C. `2gh`D. `(10)/(7)gh`

A solid sphere is rolling on a frictionless surface, shown in figure w

1.	A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity `v m//s`. If it is to climb the inclined surface then `v` should be : A. `ge sqrt((10)/(7)gh)`B. `ge sqrt(2gh)`C. `2gh`D. `(10)/(7)gh`
Answer» `(1)/(2)mv^(2)(1+k^(2)//R^(2))=mgh` `(1)/(2)mv^(2)(1+(2)/(5))=mgh` `(7)/(10)mv^(2)=mgh` `v=sqrt((10gh)/(7))` `vgesqrt((10gh)/(7))`

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A solid sphere is rolling on a frictionless surface, shown in figure with a translational velocity `v m//s`. If it is to climb the inclined surface then `v` should be : A. `ge sqrt((10)/(7)gh)`B. `ge sqrt(2gh)`C. `2gh`D. `(10)/(7)gh`

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