1.

A solid sphere of mass 2 kg rolls up a 30^(@) incline with an initial speed of 10 ms^(-1). The maximum height reached by the sphere is (g = 10 ms^(-2))

Answer»

3.5 m
7 m
10.5 m
14 m

Solution :In case of PURE rolling, `(K_(R))/(K_(T))=(2)/(5)`
`:.` Total kinetic energy `= 7//5` TIMES the translational kinetic energy. At highest point, whole of the kinetic energy will be convered into potential energy
`:. mgh=(7)/(5)((1)/(2)mv^(2))or h=(7v^(2))/(10g)=(7(10)^(2))/(10g)=(7(10)^(2))/(10xx10)=7m`


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