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A solid sphere of mass 2kgis rolling down an inclined plane of angle of inclination 30^(@). What is the agent which supplies the external torque for the rotational motion of the sphere ? Calculate torque if radius is 0.40m (g=10ms^(-2) |
Answer» SOLUTION : The force of friction between the sphere and the inclined plane SUPPLIES the external torque. Given `m=2kg,theta=30^(@),R=0.40m,g=10ms^(-2)` We know that a `=(gsintheta)/(1+(K^2)/(R^2))` Force=`ma=5/7mgsintheta` `F=5/7xx2xx10xxsin30^(@)` i.e `F=(50)/7=7.143N` |
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