1.

A solid sphere of mass 2kgis rolling down an inclined plane of angle of inclination 30^(@). What is the agent which supplies the external torque for the rotational motion of the sphere ? Calculate torque if radius is 0.40m (g=10ms^(-2)

Answer»

SOLUTION :
The force of friction between the sphere and the inclined plane SUPPLIES the external torque.
Given `m=2kg,theta=30^(@),R=0.40m,g=10ms^(-2)`
We know that a `=(gsintheta)/(1+(K^2)/(R^2))`
Force=`ma=5/7mgsintheta`
`F=5/7xx2xx10xxsin30^(@)`
i.e `F=(50)/7=7.143N`


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