1.

A solid sphere of mass M and radius R has a moment of inertia about an axis tangent to its surface is given by formula …………..

Answer»

`(2)/(5)MR^(2)`
`(7)/(5)MR^(2)`
`(2)/(3)MR^(2)`
`(5)/(3)MR^(2)`

Solution :Moment of inertia of SOLID sphere about an axis passing through its centre `I_(c )=(2)/(5)MR^(2)`
From parallel axis theorem, moment of inertia about axis TANGENTIAL to surface,
`I=I_(c)+Md^(2)`
`=(2)/(5)MR^(2)+MR^(2) [because d=R]`
`therefore I=(7)/(5)MR^(2)`


Discussion

No Comment Found