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A solid sphere of mass M and radius R has a moment of inertia about an axis tangent to its surface is given by formula ………….. |
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Answer» `(2)/(5)MR^(2)` From parallel axis theorem, moment of inertia about axis TANGENTIAL to surface, `I=I_(c)+Md^(2)` `=(2)/(5)MR^(2)+MR^(2) [because d=R]` `therefore I=(7)/(5)MR^(2)` |
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