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A solid sphere of mass M and radius R is placed on a smooth horizontal surface. It is given a horizontal impulse J at a height h above the centre of mass and sphere starts rolling then, the value of h and speed of centre of mass are – |
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Answer» `h=(2)/(5)R and v=(J)/(M)` `F XX h=(2)/(5) mR^(2)xx ALPHA` and F = ma (where `a=R alpha`) `:.` mah `=(2)/(5) mRa rArr h=(2)/(5)R` ALSO impulse = change in momentum or `J=Mv` |
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