1.

A solid sphere of mass M and radius R spins about an axis passing through its centre making 600 rpm. Its kinetic energy of rotation is

Answer»

`(2)/(5) pi^2 MR`
`(2)/(5) pi M^2 R^2`
`80 pi MR`
`80 pi^(2) MR^(2)`

Solution :Kinetic energy of ROTATION , `K_(R) = (1)/(2) I omega^(2)`
Here , `I= (2)/(5) MR^(2) , omega = (600 xx 2pi)/(60) = 20 pi` rad/s
`therefore K_(R) = (1)/(2) xx (2)/(5) MR^(2) (20 pi)^(2) = 80 pi^(2) MR^(2)`


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