A solid sphere rolls without slipping on an inclined plane of angle theta. Find its linear acceleration in the direction parallel to the surface of the inclined plane.

A solid sphere rolls without slipping on an inclined plane of angle th

1.	A solid sphere rolls without slipping on an inclined plane of angle theta. Find its linear acceleration in the direction parallel to the surface of the inclined plane.
Answer» `(5)/(7)gsintheta` `(7)/(5)gsintheta` `(3)/(5)gsintheta` `(1)/(2)gsintheta` Solution :Acceleration of body parallel to the PLANE is `a=(gsintheta)/(1+(K^(2))/(R^(2)))` but for sphere `k^(2)=(2)/(5)R^(2)` `therefore a=(gsintheta)/(1+(2R^(2))/(5R^(2)))` `therefore a=(5gsintheta)/(7)`