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A solid spherical ball and a hollow spherical ball of two different materials of densities p_(1) and p_(2) respectively have same outer radii and same mass. What will be the ratio the moment of inertia (about an axis passing through the centre) of the hollow sphere to that of the solid sphere? |
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Answer» `(p_(2))/(p_(1))(1-(p_(2))/(p_(1)))^(5/3)` ALSO, Rsolid = Rhollow = R (SAY) and `M_("solid") = M_("hollow")` `M=4/3pip_(1)R^(3)` `=4/3pip_(2)[R^(3)-R_("INNER")^(3)]rArrR^(3)-R_("inner")^(3)=(p_(1))/(p_(2))R^(3)` `rArr_("inner")^(3)=R^(3)[1-(p_(1))/(p_(2))]` `rArrR_("inner")=R[1-(p_(1))/(p_(2))]^(1//3)` ..(i) Now, ratio of their moment of inertia about the central axis will be `(I_("hollow"))/(I_("solid"))=(4/3piR^(3)p_(2)xx2/5R^(2)-4/3piR_("inner")^(3)p_(2)xx2/5R_("inner")^(2))/(2/5xx4/3piR^(3)p_(1)xxR^(2))` `=(p_(2))/(p_(1))[(R^(5)-R_("inner")^(5))/(R^(5))]=(p_(2))/(p_(1))[1-((R_("inner"))/R)^(5)]` `(I_("hollow"))/(I_("solid"))=(p_(2))/(p_(1))[1-[1-(p_(1))/(p_(2))]^(5//3)]` [From equation (i)]
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