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A solution containing 2.675 g of `CoCl_(3).6NH_(3)` (molar mass `= 267.5 g mol^(-1)`) is passed through a cation exchanger. The chloride ions obtained is solution were treated with excess of `AgNO_(3)` to give 4.73 g of `AgCl` (molar mass = `143.5 g mol^(-1)`). The formula of the complex is (At. mass of Ag = 108 u)A. `[Co(NH_(3))_(6)]Cl_(3)`B. `[CoCl_(2)(NH_(3))_(4)]Cl`C. `[CoCl_(3)(NH_(3))_(3)]`D. `[CoCl(NH_(3))_(5)]Cl_(2)` |
Answer» Correct Answer - A | |