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A solution containing 500 g of a protein per liter is isotonic with a solution containing 3.42 g sucrose per liter. The molecular mass of protein in 5 x `10^(x)`, hence x is.A. 2B. 3C. 4D. 5 |
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Answer» Correct Answer - 3 `pi1=pi2` `C_(1)=C_(2)` `((w_(1))/(m_(1)v_(1)))_("protein")=((w_(2))/(m_(2)v_(2)))_("sucrose")` `(500)/(5xx10^(x)xx1)=(3.42)/(342xx1)` `(100)/(10^(x))=(1)/(100)` `10^(x)=10^(4)` x= 4 |
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