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A solution containing `H^(+)` and `D^(+)` ions is in equilibrium with a mixture of `H_(2)` and `D_(2)` gases at `25^(@)C` . If the partial pressure of both the gases are `1.0` atm. The ration `[H^(+)]/[D^(+)]`. Given, `E_(D^(+)//D)^(@) = -0.003 C, E_("cell") = 0.006 V` :A. `1.2`B. `1.1`C. `0.11`D. `1.0` |
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Answer» Correct Answer - B `D_(2) + 2H^(+) rarr H_(2) + 2D^(+)` `E = E_(OP_(D))^(@) + E_(RP_(H))^(@) + (0.0591)/(2)"log"([H^(+)]^(2)xxP_(D_(2)))/(P_(H_(2)) xx [D^(+)]^(2))` `0.006 = 0.003 + 0 + (0.0591)/(1)"log"([H^(+)])/([D^(+)])` `(0.0591)/(1)"log"([H^(+)])/([D^(+)]) = 0.0006 - 0.003` `:. "log"([H^(+)])/([D^(+)]) = 0.0507` `:. ([H^(+)])/([D^(+)]) = 1.12` |
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