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A solution contains `25% H_(2)O, 25% C_(2)H_(5)OH` and `50%CH_(3)COOH` by mass. The mole fraction of `H_(2)O` would beA. `0.25`B. `2.5`C. `0.503`D. `5.03` |
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Answer» Correct Answer - C `X_(H_(2)O)=(n_(H_(2)O))/(n_(H_(2)O)+n_(C_(2)H_(5)OH)+n_(CH_(3)COOH))` |
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