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A solution contains 4 g of NaOH and 16.2 g of water. The mole fraction of solute and solvent are respectively.A. 0.1,0.9B. 0.2,0.8C. 0.5,0.5D. 0.4,0.6

Answer» Correct Answer - A
`n_(B)=((4g))/(("40 g mol"^(-1)))=0.1` mol
`n_(A)=(("16.3g"))/(("18 g mol"^(-1)))=0.9` mol
`X_(B)=(n_(B))/(n_(B)+n_(A))=(0.1)/((0.1+0.9))=0.1` mol
`X_(A)=1-0.1=0.9`.


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