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A solution has `1:4` mole ratio of pentane to hexane . The vapour pressure of pure hydrocarbons at `20^@C`are `440` mmHgfor pentane and `120`mmHg for hexane .The moleA. `0.549`B. `0.200`C. `0.786`D. `0.478`

Answer» Correct Answer - D
`P_(T)=p_(p)^(@)x_(p)+p_(h)^(@)x_(h)=440xx(1)/(5)+120xx(4)/(5)`
`=88+96=184, p_(p)^(@)x_(p)=Y_(p)P_(T), (88)/(184)=y_(p)`


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