A solution is prepared by adding 360 g of glucose to 864 g of water. Calculate mole fraction of glucose (molar mass of glucose = 180).

A solution is prepared by adding 360 g of glucose to 864 g of water. C

1.	A solution is prepared by adding 360 g of glucose to 864 g of water. Calculate mole fraction of glucose (molar mass of glucose = 180).
Answer» No. of moles of glucose `=(360)/(180)=2` No. of moles of water `=(864)/(18)=48` `therefore` Mole fraction of glucose `=(2)/(2+48)=(2)/(50)=(1)/(25)=0.04`

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A solution is prepared by adding 360 g of glucose to 864 g of water. Calculate mole fraction of glucose (molar mass of glucose = 180).

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