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A solution is prepared by dissolving `9.8" g of "H_(2)SO_(4)` in 54 g of water. What is the mole fraction of `H_(2)SO_(4)`?

Answer» Weight of `H_(2)SO_(4) = 9.8` g
GMW of `H_(2)SO_(4) = 98`
Number of moles of ` H_(2)SO_(4)` present in the solution = 9.8/98 = 0.1
Number of moles of `H_(2)O=54//18= 3`
Mole fraction of `H_(2)SO_(4)= 0.1//(0.1+3)=0.032`.


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