A solution of 0.1(N) KCl offers a resistance of 245 ohms. Calculate th

1.	A solution of 0.1(N) KCl offers a resistance of 245 ohms. Calculate the specific conductance and the equivalent conductance of the solution if the cell constant is 0.571 cm-1 .
Answer» Resistance = 245 ohms ∴ Conductance = \(\frac{1}{245} ohm^{-1}\) Conc. of Constant = 0.571 cm^-1 Conc. of solution = 0.1 N Specific conductance (K) = Observed conductance x Cell constant = \(\frac{1}{245}\times o.571\) = 0.00233061 ohm^-1cm^-1 ^{Equivalent conductance (}∧_eq⁾ ⁼\(\frac{k\times1000}{C_{eq}}\)⁼\(\frac{0.00233061\times1000}{0.1}\) = 23.3061 ohm^-1 cm²eq^-1

A solution of 0.1(N) KCl offers a resistance of 245 ohms. Calculate the specific conductance and the equivalent conductance of the solution if the cell constant is 0.571 cm-1 .

Answer»

Resistance = 245 ohms

∴ Conductance = \(\frac{1}{245} ohm^{-1}\)

Conc. of Constant = 0.571 cm^-1

Conc. of solution = 0.1 N

Specific conductance (K) = Observed conductance x Cell constant

= \(\frac{1}{245}\times o.571\) = 0.00233061 ohm^-1cm^-1

^{Equivalent conductance (}∧_eq⁾

⁼\(\frac{k\times1000}{C_{eq}}\)⁼\(\frac{0.00233061\times1000}{0.1}\)

= 23.3061 ohm^-1 cm²eq^-1