A solution of 0.1M KMnO_4is used for the reaction S_(2)O_(3)^(-2) + 2 MnO_(4)^(-) + H_(2)OrarrMnO_(2) +SO_(4)^(2-)+ OH^(-) . The volume of KMnO_4required to react 0.158gm of Na,s,o, is (MW = 158)

A solution of 0.1M KMnO_4is used for the reaction S_(2)O_(3)^(-2) + 2

1.	A solution of 0.1M KMnO_4is used for the reaction S_(2)O_(3)^(-2) + 2 MnO_(4)^(-) + H_(2)OrarrMnO_(2) +SO_(4)^(2-)+ OH^(-) . The volume of KMnO_4required to react 0.158gm of Na,s,o, is (MW = 158)
Answer» <html><body><p>13.33 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a> <br/>6.66 ml <br/>3.33 ml<br/> 26.67 ml </p>Solution :No. of <a href="https://interviewquestions.tuteehub.com/tag/milli-560824" style="font-weight:bold;" target="_blank" title="Click to know more about MILLI">MILLI</a> equivalents of `KMnO_4` = No of milli equivalents of <a href="https://interviewquestions.tuteehub.com/tag/thiosulphate-1414356" style="font-weight:bold;" target="_blank" title="Click to know more about THIOSULPHATE">THIOSULPHATE</a> ions <br/> `<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> xx0.1 xx3=(0.158)/(((158)/<a href="https://interviewquestions.tuteehub.com/tag/8-336412" style="font-weight:bold;" target="_blank" title="Click to know more about 8">8</a>))xx1000` <br/> `V = 80/3 =26.67 ml`</body></html>