A solution of `CuSO_(4)` is electrolysed for 10 minutes with a current of `1.5` amperes. What is the mass of copper deposited at the cathode ?

A solution of `CuSO_(4)` is electrolysed for 10 minutes with a current

1.	A solution of `CuSO_(4)` is electrolysed for 10 minutes with a current of `1.5` amperes. What is the mass of copper deposited at the cathode ?
Answer» `t=600` s charg = current `xx` time `=1.5 A xx 600s= 900C` According to the reaction : A`Cu_((aq))^(2+)+2e^(-) =Cu_((s))` We require 2F or `2xx 96487` C to deposite 1 mol or 63 g of Cu. For 900 C, the mass of Cu deposited `=(63 g mol ^(-1)xx900C) //(2xx96487C mol ^(-1))=0.2938g`

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A solution of `CuSO_(4)` is electrolysed for 10 minutes with a current of `1.5` amperes. What is the mass of copper deposited at the cathode ?

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