1.

A solution of Glucose Of C6 H12 O6 in H2O Given:10gm of Glucose dissolved in H2O and the solution is made to 100cm3 in a volumetric flask. Calculate Molarlity of the solution ?​

Answer»

Molalityof a solution is defined as the number of moles of solute dissolved per kg of SOLVENT.

C H O

6 12 6

= 10\% \: by \: <klux>WEIGHT</klux>

THUS in 100 G solution mass of glucose = 10 g and of water =90 g

Number of moles of glucose =

mass/molar mass

n= 10/ 180= 1/18 mol

Mass of solvent = 90 g= 0.09 kg

Molality, m= (1/18) / 0.09

m= 100/18×9=0.617 molal≈0.6 molal

The molality of a solution of glucose (C H O )

6 12 6

in water is labelled as 10% by weight is 0.617 molal.


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