InterviewSolution
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InterviewSolution
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A solution of glycerol `(C_(3)H_(8)O_(3))` in water was prepared by dissolving some glycerol in `500g` of water. This solution has a boiling point of `100.42^(@)C` while pure water boils at `100^(@)C`. What mass of glycerol was dissolved to make the solution ? (`K_(b)` for water `= 0.512 K kg mol^(-1)`) |
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Answer» `W_(H_(2)O) = 500 g = 0.5 kg, T_(b)^(0) = 100^(0)CW_("glycerol")` `:. T_(b) = 100.42 .^(@)C`. `DeltaT_(b) = 0.42.^(@)C` `DeltaT_(b) = K_(bm)` `DeltaT_(b) = (W_("glycerol"))/(W_(H_(2)O) xx M_("glycerol"))` `0.42 = 0.512 xx (W_("glycerol"))/(0.5 xx 92)` `W_("glycerol") = (0.42 xx 0.5 xx 92)/(0.512) = 37.73 g`. |
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