InterviewSolution
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InterviewSolution
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A solution of `KMnO_4` is reduced to various products depending upon its pH. At pH lt 7 it is reduced to a colourless solution (A), at pH = 7 it forms a brown precipitate (B) and at pH gt 7 it gives a green solution ( C), (A),(B) and( C) areA. `{:("(A)","(B)","(C)"),(Mn^(2+),MnO_2,MnO_4^(2-)):}`B. `{:("(A)","(B)","(C)"),(MnO_2,mn^(2+),MnO_4^(2-)):}`C. `{:("(A)","(B)","(C)"),(Mn^(2+),MnO_4^(2-),MnO_2):}`D. `{:("(A)","(B)","(C)"),(MnO_4^(2-),Mn^(2+),MnO_2):}` |
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Answer» Correct Answer - A At pH lt 7, in acidic medium `MnO_4^(-)+8H^(+)+5e^(-) to underset(("brown precipitate"))(MnO_2)+4OH^(-)` At pH gt 7, in alkaline medium `MnO_4^(-)+e^(-)to underset(("green"))(MnO_4^(2-))` |
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