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The colour of `K_(2)Cr_(2)O_(7)` changes from red-orange to lemon-yellow on treatment with `KOH_((aq.))`, because of:A. The reduction of `Cr^(VI)` to `Cr^(III)`B. The formation of chromium hydroxidedC. The conversion of dichromate to chromateD. The oxidation of potassium hydroxide to potassium peroxide |
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Answer» Correct Answer - C The conversion of dichromate to chromate. `K_(2) Cr_(2) O_(7) + 2 KOH rarr underset(yellow) underbrace(2K_(2) Cr O_(4)) + H_(2) O` |
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