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A solution of `KMnO_(4)` on reduction yields either a coloureless solution or a brown precipitate or a green solution depending on Ph of the solution. What different stages of the reduction do these represent and how are they carried out ? |
Answer» `KMnO_(4)` is anoxidizing agent. Its oxidising behaviour depends upon pH of the solution. In acidic medium `(pH lt 7) , MnO_(4)^(-) + 8H^(+) + 5e^(-) rarr underset("(Coloureless)")(Mn^(2+)) + 4H_(2)O` In alkaline medium `( pH gt 7) , MnO_(4)^(-) + e^(-) rarr underset("(Green)")(MnO_()^(2-))("manganese")` In neutral medium `( pH = 7 ) , MnO_(4)^(-) + 2H_(2)O + 3e^(-) rarr underset("(Brown ppt.)")(MnO_(2)) + 4OH^(-)` |
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