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InterviewSolution
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A solution of `[Ni(H_(2)O)_(6)]^(2+)` is green but a solution of `[Ni(CN)_(4)]^(2-)` is colourless Explain. |
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Answer» In `[Ni(H_(2)O)_(6)]^(2+) Ni is in +2` oxidation state and having unpaired electrons which do not pair in the presence of the weak `H_(2)O` ligand Hence, it is coloured The d-d transition absorbs red light and the complementary light emitted is green In `[Ni(CN)_(4)]^(2-)` Ni is also in +2 oxidation state and having `3d^(8)` electronic configuration But in presence of strong ligand `CN^(-)` the two unpaired electrons in the 3d orbitals pair up, Thus, there is no unpaired electron present Hence, it is colourless. |
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