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A solution of protein (extracted from carbs) was prepared by dissolving `0.75 g` in `125 cm^(3)` of an aqueous solution. At `4^(@)C` and osmotic pressure rise of `2.6 mm` of the solution was observed. Then molecular weight of protein is (assume density of solution is `1.00 g//cm^(3)`):A. (a) `9.4 xx 10^(5)`B. b) `5.4 xx 10^(5)`C. ( c) `5.4 xx 10^(10)`D. (d) `9.4 xx 10^(10)` |
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Answer» Correct Answer - B Given `h = 2.6 mm` `:. pi = hdg = (2.6)/(10) xx 1 xx 980 " dyne " cm^(-2)` Also `pi = (w)/(V.m)ST` (in `C.G.S`. System) or `(2.6 xx 1 xx 980)/(10) = (0.75 xx 8.314 xx 10^(7) xx 277)/(125 xx m)` `:. m = 5.4 xx 10^(5)` |
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