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A solution of sucrose (molar mass `= 342 "g mol"^(-1)`) has been prepared by dissolving 68.5g of sucrose in 1000g of water. The freezing point of the solution obtained will be : (`K_(f)` for water `= 1.86 "K kg mol"^(-1)`)A. `-0.372^(@)C`B. `-0.520^(@)C`C. `+0.372^(@)C`D. `-0.570^(@)C` |
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Answer» Correct Answer - A `Delta T_(f) = K_(f) m` Here, `m = 68.5/(342 xx 1)` `:. Delta T_(f) = 0.2000 xx 1.86 = 0.3725^(@)C` `T_(f) = 0^(@) -0.3725^(@)C= -0.3725^(@)C` |
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