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A solution which is `10^(-3)M` each in `Mn^(2+), Fe^(2+), Zn^(2+)`, and `Hg^(2+)` it treated with `10^(-16)M` sulphide ion. If the `K_(sp)` of `MnS, FeS, ZnS`and `HgS` are `10^(-15), 10^(-23), 10^(-20)`,and `10^(-54)`, respectively, which one will precipitate first?A. `FeS`B. `MgS`C. `HgS`D. `ZnS`

Answer» Correct Answer - C::D


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