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In a 500mL falsk, the degree of dissociation of `PCI_(5)` at equilibrium is `40%` and the initial amount is 5 moles. The value of equilibrium constant in mol `L^(-1)` for the decomposition of `PCI_(5)` isA. `2.33`B. `2.66`C. `5.32`D. `4.66` |
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Answer» Correct Answer - B `{:(,PCI_(5),hArr,PCI_(3),+,CI_(2)),("Initial moes",5,,0,,0),("Moles at equilibrium",5(1-alpha),,5alpha,,5alpha),("Conc. at equilibrium",(5(1-alpha))/(0.5),,(5alpha)/(0.5),,(5alpha)/(0.5)):}` `alpha = 40% = 0.4` `K_(C) = ([PCI_(3)][CI_(2)])/([PCI_(5)]) =(((5xx 0.4)/(0.5)))/(((5xx0.6)/(0.5))) =2.66 mol//L` |
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