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A sound increases its decibel reading from `20 "to" 40 dB`. This means that the intensity of the soundA. is doubledB. is `20 `times greaterC. is `100` times greaterD. is the old intensity `20` |
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Answer» Correct Answer - C The decibel scale is logarithmic `dB = 10 log(I//I_(0))`. Each increase in intensity by a power of ten increases the decibel reading by `10 units`. Hence , to increase the decibel reading by `20` ,there should be an increase in the intensity of `10 xx10 = 100`. |
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