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A sound wave of frequency 1000 Hz and travelling with speed 340 m/s is reflected from the closed end of the tube. At what distance from that end will the adjacent node occur? |
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Answer» Data : n = 1000 Hz, v = 340 m/s The wavelength of the stationary wave set up in the tube, λ = \(\frac vn\). The distance between successive nodes = \(\frac{λ}2\) = \(\frac{v}{2n}\) = \(\frac{350}{2(1000)}\) = 0.17 m = 17 cm |
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