1.

A source and observer are approaching one another with the relative velocity 40ms^(-1). If the true source frequency is 1200 Hz, deduce the observed frequency under the following conditions: (i) All velocity is in the source alone. (ii) All velocity is in the observer alone. (iii) The source moves in air at 100ms^(-1) towards the observer, but the observed also moves with the velocity v_(0) in the same direction. (Velocity of sound 340 m/s)

Answer»

Solution :Here V=1200Hz, `v=340ms^(-1)`
Relative VELOCITY `=40MS^(-1)`
(i) Here source move towards the stationary
observer, `v_(s)=+40ms^(-1),v_(0)=0`

`"Train"overset(S""+ve""v_(s))tooverset(*)"Observer "v_(0)=0`
`v'=((v-v_(0)))/((v-v_(0)))xxv=(340-0)/(340-40)xx1200`
`=(340xx1200)/(300)=1360Hz`.
(II)Here observer MOVES towards the stationary source,
`v_(0)=-40ms^(-1),v_(s)=0`
`S*v_(s)=0""overset(-ve""v_(0)""O)to`
`v'=(v-v_(0))/(v-v_(s))xxv=(340+40)/(340-0)xx1200`
`=(380)/(340)xx1200=1341Hz`.

(iii)Here observer and source move in the same direction,
`v_(s)=100ms^(-1),v_(0)=100-40=60ms^(-1)`
`overset(S""+ve""v_(s))to""overset(S""+ve""v_(s))to`
`v'=(v-v_(0))/(v-v_(s))xxv=(340-60)/(340-100)xx1200`
`=(280)/(240)xx1200=1400Hz`.


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