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    				| 1. | A source emitting light of wavelengths 480 nm and 600 nm is used in a double slit interference experiment. The separation between the slits is 0.25 mm and the interference is observed on a screen placed at 150 cm from the slits. Find the linear separation between the first maximum (next to the central maximum) corresponding to the two wavelengths. | 
| Answer» Correct Answer - B We know that the first maximum (next to central maximum) occurs at `y=(lamdaD)/d` `Given that lamda_1=480nm` `lamda_2=600nm` D=150cm=1.5m` and `d=0.25mm` `=0.25xx10^-3m` so, `y_1=(Dlamda_1)/d` `=((1.5)xx480xx10^-9)/(0.25xx10^-3)` `=2.88mm` `y_2=((1.5)xx600xx10^-9)/(0.25xx10^-3)` so the separation between these two bright fringes is given by `:. Separation `=y_2-y_1` `=3.60-2.88=0.72mm. | |