1.

A source of sound and a listener are approaching each other with a speed of 40ms^(-1)The apparent frequency of a note produced by the source is 400 Hz. Then its true frequency is (velocity of sound in air = 360 ms^(-1) )

Answer»

320 HZ
400 Hz
360 Hz
420 Hz

Solution :`f. = ((v + v_(0))/(v - v_(s))) f implies 400 = [(360 + 40)/(360 - 40)] f implies f = 320` Hz


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