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| 1. |
A source of sound and a listener are approaching each other with a speed of 40ms^(-1)The apparent frequency of a note produced by the source is 400 Hz. Then its true frequency is (velocity of sound in air = 360 ms^(-1) ) |
| Answer» Solution :`f. = ((v + v_(0))/(v - v_(s))) f implies 400 = [(360 + 40)/(360 - 40)] f implies f = 320` Hz | |