A source of sound attached to the bob of a simple pendulum execute `SHM` . The difference between the apparent frequency of sound as received by an observer during its approach and recession at the mean frequency of the source . The velocity of the source at the mean position is ( velocity of sound in the air is `340 m//s`) [Assume velocity of sound `lt lt` velocity of sound in air ]A. `1.4 m//s`B. `3.4 m//s`C. `1.7 m//s`D. `2.1 m//s`

A source of sound attached to the bob of a simple pendulum execute `SH

1.	A source of sound attached to the bob of a simple pendulum execute `SHM` . The difference between the apparent frequency of sound as received by an observer during its approach and recession at the mean frequency of the source . The velocity of the source at the mean position is ( velocity of sound in the air is `340 m//s`) [Assume velocity of sound `lt lt` velocity of sound in air ]A. `1.4 m//s`B. `3.4 m//s`C. `1.7 m//s`D. `2.1 m//s`
Answer» Correct Answer - B ` f_(1) = f_(0) ((V_(0))/(V_(0) - V)) f_(2) = f_(0)((V_(0))/(V_(0) + V))` `f_(1) - f_(2) = f_(0) V_(0) ((1)/( V_(0) - V) - (1)/( V_(0) + V))` ` = f_(0) V_(0) (V_(0) + V - V_(0) + V)/( V_(0)^(2) - V^(2)) = f_(0) V_(0) xx ( 2V)/( V_(0)^(2)) = f_(0) ( 2V)/( V_(0))` given `( 2 Vf_(0))/(V_(0)) = 0.02 xx f_(0) rArr V = 0.01 V_(0) = 3.4 m//s`.

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