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A source of sound is travelling with a velocity of `30(m)/(s)` towards a stationary observer. If actual frequency of source is 1000 Hz and the wind is blowing with velocity `20(m)/(s)` in a direction at `60^@C` with the direction of motion of source, then the apparent frequency heard by observer is (speed of sound is `340(m)/(s)`)A. 1011 HzB. 1000 HzC. 1094 HzD. 1086 Hz |
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Answer» Correct Answer - C `f=((v+v_m)/(v+v_m-v_(source)))1000` `=((340+20cos60^@)/(340+20cos60^@-30))1000` `=1094Hz` |
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