1.

A source producing sound of frequency 170 Hz is approaching a stationary observer with a velocity 17 ms^(-1). The apparnet change in the wavelength of sound heard by the observer is (speed of sound in air =340 ms^(-1))

Answer» <html><body><p>`0.2 m`<br/>`0.1 m`<br/>`0.5 m`<br/>`0.4 m`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`lambda=(v)/(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>)=(340)/(<a href="https://interviewquestions.tuteehub.com/tag/170-278357" style="font-weight:bold;" target="_blank" title="Click to know more about 170">170</a>)=<a href="https://interviewquestions.tuteehub.com/tag/2m-300757" style="font-weight:bold;" target="_blank" title="Click to know more about 2M">2M</a>` <br/> `n'=(340)/(340-17)xx170` <br/> `n=178.9 Hz` <br/> Now, `lambda'= (v)/(n)=(340)/(178.9)=1.9` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> lambda- lambda'=2-1.9=0.1 m`</body></html>


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