InterviewSolution
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InterviewSolution
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A source `S_(1)` is producing `10^(15)` photons//s of wavelength `5000 Å` Another source `S_(2)` is producing `1.02 xx 10^(15)` photons per second of wavelength `5100 Å`. Then `("power of" `S_(2))//("power of" S_(1))` is equal toA. `1.00`B. `1.02`C. `1.04`D. `0.98` |
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Answer» Correct Answer - A Number of photons emitted per second ` n = (p)/(((hc)/(lambda)))` `:. P = ( nhc)/(lambda)` `rArr (P_(2))/(P_(1)) = (n_(2) lambda_(1))/(n_(1) lambda_(2)) = (1.02 xx 10^(15) xx 5000)/(10^(15) xx 5100) = 1` |
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